Question

explain the following observation. When 3-methylbutan-2-ol is treated with HBr, a single alkyl bromide is isolated, resulting from 1,2, shift. When 2-methylpropan-1-ol is treated with HBr no rearrangement occurs to form alkyl bromide

Answer 1

1. For the first reaction, there is Carbonation and rearrangement

2. For the second reaction, No Carbonation, No rearrangement.

Step-by-step explanation:

See attached screenshot below