Question

A piece of aluminum (bulk modulus 7.1 x 1010 N/m2) is placed in a vacuum chamber where the air pressure is 0.781 x 105 Pa. The vacuum pump is then turned on and the pressure is further reduced to zero. Determine the fractional change V/V0 in the volume of the aluminum

Answer 1

`{(\Delta V)/(V)}=11* 10^(-7)`

Step-by-step explanation:

Given that

Bulk modulus ,K = 7.1 x 10¹⁰ Pa

The pressure P₁ = 0.781 x 10⁵ Pa

The final pressure P ₂ = 0 Pa

We know that bulk modulus given as

`K=(\Delta P)/((\Delta V)/(V))`

Now by putting the values

`K=(\Delta P)/((\Delta V)/(V))`

`7.1* 10^(10)=(0.781* 10^5)/((\Delta V)/(V))`

`{(\Delta V)/(V)}=(0.781* 10^5)/(7.1* 10^(10))`

`{(\Delta V)/(V)}=11* 10^(-7)`

Therefore fractional change will be 11 x 10⁻⁷.