Question

A mixture of three gases, A, B, and C, is

at a total pressure of 7.47 atm. The partial
pressure of gas A is 1.59 atm; that of gas B is
3.78 atm. What is the partial pressure of gas
C?
Answer in units of atm

Answer 1

To find the partial pressure of gas C in a mixture of gases A, B, and C, subtract the sum of the partial pressures of A and B from the total pressure. In this case, the partial pressure of gas C is 2.10 atm.

Step-by-step explanation:

Dalton's law of partial pressures states that the total pressure is equal to the sum of the partial pressures. In this case, the total pressure is 7.47 atm, and the partial pressures of gases A and B are 1.59 atm and 3.78 atm, respectively. To find the partial pressure of gas C, subtract the sum of the partial pressures of A and B from the total pressure:

Partial pressure of gas C = Total pressure - Partial pressure of gas A - Partial pressure of gas B

= 7.47 atm - 1.59 atm - 3.78 atm

= 2.10 atm

Answer 2

2.1 atm is the partial pressure of gas C.

Step-by-step explanation:

to calculate partial pressure of gas C we will use Dalton's law.

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.

`P_T=p_(1)+p_(2)+p_(3)...p_(n)`

where,

`P_T` = Total pressure

`p_(1)` = partial pressure of gas-1

`p_(2)` = partial pressure of gas-2

`p_(3)` = partial pressure of gas-3

`p_(n)` = partial pressure of nth gas in the mixture

We have:

`P_T= 7.47 atm`

`p_(A)=1.59 atm`

`p_(B)=3.78 atm`

`p_(C)=?`

Now put all the given values is expression, we get the partial pressure of the
`O_2` gas.

`P_T=p_(A)+p_(B)+p_(C)`

`7.47 atm=1.59 atm+3.78 atm+p_(C)`

`p_(C)=2.1 atm`

2.1 atm is the partial pressure of gas C.