Question

HURRYYY

A rectangular pool is surrounded by a walk 2 meters wide. The pool is 3 meters longer than its width. If the total area of the pool and walk is 188 square meters more than the area of the​ pool, find the dimensions of the pool.

Answer 1

width=20m,length=23m

Explanation:

as shown in the figure which is attached

let width of pool =x

⇒ length of pool=x+3

width of walk =2

⇒width of outer boundary of walk=x+4 (2 on each side of pool)

length of outer boundary of walk=x+3+4=x+7

area of pool =x×(x+3)

area of walk+pool=(x+4)×(x+7)

given

total area of the pool and walk is 188 square meters more than the area of the​ pool

⇒(x+4)×(x+7)=188+x×(x+3)

⇒8x=160

x=20m

dimensions of pool

widh=20m

length=20+3=23m