Question

An astronaut who is repairing the outside of her spaceship accidentally pushes away a 99.1 cm long steel rod, which flies off at 11.9 m/s , never to be seen again. As it happens, the rod is oriented perpendicularly to the magnetic field in that region of space. The rod is moving perpendicularly to its length as well as to the direction of the magnetic field. The magnetic field strength there is 7.11 mT . What is the magnitude of the EMF, in millivolts, induced between the ends of the rod?

Answer 1

83.847519 mV

Step-by-step explanation:

B = Magnetic field strength = 7.11 mT

L = Length of steel rod = 99.1 cm

v = Velocity of steel rod = 11.9 m/s

The induced electro motive force is given by

`E=BLV\\\Rightarrow E=7.11* 10^(-3)* 0.991* 11.9\\\Rightarrow E=0.083847519\ V=83.847519\ mV`

The magnitude of the EMF induced between the ends of the rod is 83.847519 mV