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A 0.25" diameter A36 steel rivet connects two 1" wide by .25" thick 6061-T6 Al strips in a single lap shear joint. The shear strength of steel is 0.58oy. What is the maximum load before yielding? A. 2313 psi B. 1025 psi C. 3207 psi D. 1654 psi

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6 votes

Answer:

Option B

1025 psi

Step-by-step explanation:

In a single shear, the shear area is
\frac {\pi d^(2)}{4}=\frac {\pi 0.25^(2)}{4}

The shear strength=
0.58\sigma_y and in this case
\sigma_y=36 000 psi

Shear strength=
\frac {Load}{Shear area} hence making load the subject then

Load=Shear area X Shear strength

Load=
\frac {\pi 0.25^(2)}{4} * 0.58* 36000\approx 1025 psi

User Abraham Brookes
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