Question

Two identical metal spheres A and B are in contact. Both are initially neutral. 1.0×1012 electrons are added to sphere A, then the two spheres are separated. Afterward, what are the charge of A and the charge of B?

Answer 1

`Q_A=80 nC`,
`Q_B=80 nC`,

Step-by-step explanation:

Knowing both spheres are identical means after the equilibrium both will have equal charge so added
`1.0x10^(12) e`

So to determine the charge of both spheres can use

`Q_A=Q_B`

`Q=1.6x10^(-19)C`

`Q_A=Q_B=Q_(total)`

`Q_(total)= - 1.0x10^(12)C * - 1.6x10^(-19)C`

`Q_(total)=1.6x10^(-7)C`

Both spheres are identical so

`Q_A=Q_B=(Q_(total))/(2)`

`Q_A=Q_B=(1.6x10^(-7))/(2)=80x10^(-9)C`