Question

Will, Sue and Micah went to dinner. Will paid 1/4 of the bill. Micah and Sue paid in the ratio of 1:3. If Sue paid $15 more than Will, how much did dinner cost in total?

Answer 1

The dinner cost was $ 48

Explanation:

Let the dinner cost was $ x

Will paid x /4

Micah paid 1/ 4 of remaining ( 1 − 1 /4 ) x = 3/4 x

i.e

4 /16x

Sue paid 3/4 of remaining ( 1 − 1 /4 ) x = 3/4x

i.e

9/16 x

Sue paid $ 15 more than Will.

∴ 9/16 x -1 /4 x = 5/16x=15

or

x=$48

Will paid 48 /4 = $ 1 2, Miah paid 4 /16. 48 = $ 12

,Sue paid 9/16⋅ 48= $ 27

The dinner cost was $ 48

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