Question

Assume that a particle moves in a velocity field defined by V (x, y) = (x + 6)i + (y − 3)j. Find the path of a particle with initial starting point (1, 1).

Answer 1

`V(1,1)=7i-2j`

Step-by-step explanation:

V(x,y)=(x+6)i+(y-3)j ............eq1

As intial point are given (1,1)

which means x=1,y=1

put these values in eq1

V(1,1)=(1+6)i+(1-3)j

V(1,1)=7i-2j

And its magnitude given as

|V(1,1)|=
`\sqrt{(7)^(2)+(-2)^(2)  }`

|V(1,1)| =7.28