Answer:
The correct equation for g(x) is

Explanation:
The given graph in the red represents the curve for the graph g(x).
Now as we observe: The graph cuts y - axis at (0,3)
⇒The value of graph g (x) = (0,3), when x = 0 and y = 3
or, the y - intercept of g(x) = 3
or, g(0) =3
Now, the given equation are:

or g(0) ≠ 3
So, A is NOT the required equation.

or g(0) = 3
So, B is the required equation.

or g(0) ≠ 3
So, C is NOT the required equation.

or g(0) ≠ 3
So, D is NOT the required equation.
Hence, the correct equation for
