Question

A 81.0 kg diver falls from rest into a swimming pool from a height of 4.70 m. It takes 1.84 s for the diver to stop after entering the water. Find the magnitude of the average force exerted on the diver during that time.

Answer 1

Step-by-step explanation:

The given data is as follows.

height (h) = 4.70 m, mass = 81.0 kg

t = 1.84 s

As formula to calculate the velocity is as follows.

`\\u` = 2gh

=
`2 * 9.8 m/s^(2) * 4.70 m`

= 92.12
`s^(2)`

As relation between force, time and velocity is as follows.

F =
`(m * \\u)/(t)`

Hence, putting the given values into the above formula as follows.

F =
`(m * \\u)/(t)`

=
`(81.0 kg * 92.12 s^(2))/(1.84 s)`

= 4055.28 N

Thus, we can conclude that the magnitude of the average force exerted on the diver during that time is 4055.28 N.