Question

A stretched string of length L is observed to vibrate in seven equal segments when driven by a 686-Hz oscillator. What oscillator frequency will set up a standing wave so that the string vibrates in two segments?

Answer 1

Answer: 196 Hz

Explanation:

F1 = F7 ÷ 7

= 686/ 7

Therefore F1 = 98Hz

Thus Oscillator frequency so that the string vibrates in 2 segments will be:-

F2 = (n)(F1)

= (2)(98)

F2= 196Hz