Answer:
+0.52m
Step-by-step explanation:
The force applied by the archer is directly proportional to the displacement of the bow string provided the elastic limit of the string is not exceeded.
= kx
k = string constant
x = string extension
![x = (F_(applied) )/(k)](https://img.qammunity.org/2020/formulas/physics/college/9fo63447ozpkrevjqoxszfatcj55twi5rl.png)
![x = \frac{+280N} }{540N/m}](https://img.qammunity.org/2020/formulas/physics/college/qab1zt3mlr4csn0kf1ih5zwzuc9nwhh9wz.png)
![x = (F_(applied) )/(k)](https://img.qammunity.org/2020/formulas/physics/college/9fo63447ozpkrevjqoxszfatcj55twi5rl.png)
x = +0.5185m
x = +0.52m
The displacement of the bow string is +0.52m