Question

Air at 25°C and 5 atm is throttled by a valve to 1 atm. If the valve is adiabatic and the change in kinetic energy is negligible, determine the exit temperature of air. Solve using appropriate software.

Answer 1

`T_(2) = 25^(\circ)C`

Solution:

As per the question:

Temperature,
`T_(1) = 25^(\circ)C`

Pressure,

Therefore, from the eqn:

`Q - W = \Delta h + \Delta KE`

We can write:

`\Delta h = h_(1) - h_(2) = 0`

`\Delta h = C_(p)\Delta T`

`C_(p)(T_(2) - T_(1)) = 0`

Thus

`T_(1) = T_(2) = 25^(\circ)C`

where

`T_(2)` = Exit temperature