Question 1

Air at 25°C and 5 atm is throttled by a valve to 1 atm. If the valve is adiabatic and the change in kinetic energy is negligible, determine the exit temperature of air. Solve using appropriate software.

Question 2

Answer:

$T_(2) = 25^(\circ)C$

Solution:

As per the question:

Temperature,
$T_(1) = 25^(\circ)C$

Pressure,
$P_(1) = 5 atm[\tex]Now,We know that the process of throttling occurs in adiabatic conditions where no heat is transferred in between the system and the surrounding, i.e., Q = 0Thus no work is done in this process, i.e., W = 0Enthalpy also remains same from one state to the other state, i.e., [tex]\Delta h = 0$

Therefore, from the eqn:

$Q - W = \Delta h + \Delta KE$