Question

How many isomers will form in the monochlorination reaction of 2,3−dimethylbutane under radical substitution conditions? What kind(s) of monochlorination products will form (choose all that apply)?

A. 1°
B. 2°
C. 3°
D. allylic

Answer 1

A and C

Step-by-step explanation:

The monochlorination is a reaction in which we have to add only one Cl to the molecule. In this case we only have two types of carbons. Primary (the methyl groups) and the tertiary (the carbons in the middle).

Therefore we only have 2 type of isomers. The first one in which the Cl would bond to the primary carbons, the primary alkyl halide (1-chloro-2,3-dimethylbutane) and the second one in which the Cl would bond to the tertiary carbons, the tertiary alkyl halide (2-chloro-2,3 -dimethylbutane).

See the figure