Answer:
The length of the diagonal is closest to 51 cm.
Explanation:
Given:
TV screen is 41 cm long and 31 cm high.
Now, to find the length of the diagonal.
By using pythagorean theorem:
leg 1 = 41 cm, leg 2 = 31 cm.
Let the hypotenuse be
.
(leg 1)² + (leg 2)² = hypotenuse²
![41^(2) +31^(2)=x^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ghymiv1hq3w2owzf0srelm042dd7eou2nq.png)
⇒
![1681+961=x^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/i2sssh523a9zgdzef3le5eqb3pwkr8oew0.png)
⇒
![2642=x^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mdbmyw0w6d6v1jvkgyy269jjeuqaq3s437.png)
Using square root on both sides we get:
⇒
![51.40=x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gig13bjejpu81wu08qjnd1hvlt7mu6z1qb.png)
So, the length of the diagonal = 51.40 cm.
By rounding off of 51.40cm it becomes 51 cm.
Therefore, the length of the diagonal is closest to 51 cm.