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If 0.771 g of O3 reacts with 0.663 g of NO, how many grams of NO2 will be produced?

1 Answer

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Answer:

Mass = 0.92 g

Step-by-step explanation:

Given data:

Mass of O₃ = 0.771 G

Mass of NO₂ = 0.663 g

Mass of NO₂ produced = ?

Solution:

Chemical equation:

O₃ + NO → NO₂ + O₂

Number of moles of O₃ :

Number of moles = mass/ molar mass

Number of moles = 0.771 g/ 48 g/mol

Number of moles = 0.02 mol

Number of moles of NO:

Number of moles = mass/ molar mass

Number of moles = 0.663 g/ 30 g/mol

Number of moles = 0.02 mol

Now we will compare the moles of NO₂ with NO and O₃ .

NO : NO₂

1 : 1

0.02 : 0.02

O₃ ; NO₂

1 : 1

0.02 : 0.02

Mass of NO₂:

Mass = number of moles × molar mass

Mass = 0.02 mol × 46 g/mol

Mass = 0.92 g

User Scott Wood
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