Question

During an all-night cram session, a student heats up a 0.607 liter (0.607 x 10- 3 m3) glass (Pyrex) beaker of cold coffee. Initially, the temperature is 16.2 °C, and the beaker is filled to the brim. A short time later when the student returns, the temperature has risen to 93.5 °C. The coefficient of volume expansion of coffee is the same as that of water. How much coffee (in cubic meters) has spilled out of the beaker?

Answer 1

Answer: 0.00000938422m^3

Step-by-step explanation:

dV=Vø*β*(t1-tø)

The parameters are

dV is the change in volume after temperature increase

Vø =0.607 *10^-3m3 is the initial vokume of coffe at 16.2^0 C

β= coefficient of volume expansion of water at 16.2^0 C is 0.0002/0C

t1= 93.5^0C final temperature

tø=16.2^0 C

Therefore

dV=0.607 *10^-3 *0.0002*(93.5-16.2)

dV= 0.00000938422m^3

This is the volume of coffee that will spill over the container