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A 20-liter cylinder contains 4 moles of natural gas. The temperature of the cylinder is 274 K. Assuming that the gas is ideal and using the universal gas constant of 0.08206 L-atm/mol-K, what is the approximate pressure in the cylinder?

A.
54.8 atm
B.
112.4 atm
C.
4.5 atm
D.
22.5 atm
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1 Answer

7 votes

Answer:

4.5 atm

Step-by-step explanation:

We are given;

  • Volume of the cylinder as 20 L
  • Moles of the gas as 4 moles
  • Temperature of the gas as 274 K
  • Universal gas constant as 0.08206 L-atm/mol-K

We are required to determine the pressure in the cylinder.

  • We are going to use the ideal gas equation;
  • According to the ideal gas equation;

PV = nRT

Rearranging the formula;

P = nRT ÷ V

Replacing the values of the known variables;

P = (4 mol × 0.08206 L-atm/mol-K × 274 K) ÷ 20 L

= 4.497 atm

= 4.50 atm

Therefore, the pressure in the cylinder is 4.5 atm

User Trashrobber
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