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What is 5x-4y=-7 (-20,-8)in slope intercept form

User Zurab
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1 Answer

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For this case we have that by definition, the equation of the line of the slope-intersection form is given by:


y = mx + b

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

We have the following equation:


5x-4y = -7

We manipulate algebraically to write the equation of the slope-intersection form:


-4y = -7-5x\\4y = 5x + 7\\y = \frac {5} {4} x + \frac {7} {4}

We check if the given point belongs to the equation:


y = \frac {5} {4} (- 20) + \frac {7} {4}\\y = -25 + \frac {7} {4}\\y = \frac {-100 + 7} {4}\\y = - \frac {93} {4}

The point does not belong to the equation.

ANswer:


y = \frac {5} {4} x + \frac {7} {4}

User Malitta N
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