Answer: A X Z is 98 Nb 41
Step-by-step explanation:
In balancing nuclear equations, we observe the following rules:
I. The total number of protons and neutrons in the products and reactants must be the same ( conservation of mass number ).
II. The total number of nuclear charges in the products and reactants must be the same ( conservation of atomic number ).
Examples: Balance the following nuclear equations ( that is, identify the product X )
I. 21284Po = 20882Pb + X
II. 13755Cs = 13756Ba + X
Solution
I. 21284Po = 20882Pb + 4He2
II. 13755Cs = 13756Ba + 0e-1
So, for (I) X is an alpha particle, (II) X is an electron.
For your question, the nuclear equation is:
(a) 23392U + 10n = 13351 Sb + 98Nb41 + 3 10n
Check to see if the equation is balanced:
Mass number of reactants: 233+1= 234
Mass number of products:
133+98+(3x1) = 234
Nuclear charge of reactants:
92+0 = 92
Nuclear charge of products:
51+41+(3x0) = 92.
This reaction (a) is a nuclear fission reaction.
Nuclear fission is a process in which a heavy nucleus ( mass number greater than 200 ) divides to form smaller nuclei of intermediate mass with a release of energy and radiation.
This is applied in the design of the atomic or fission bomb.