Question

What force must be applied to push a carton weighing 245 N up a 15.0° incline, if the coefficient of kinetic friction is 0.340? Assume the force is applied parallel to the incline and the velocity is constant.

Answer 1

143.815 N

Step-by-step explanation:

when a person is pushing a carton in an inclined plane there is two forces acting against the applied force,

• component of gravity or mgsinθ

• friction or μmgcosθ

the carton goes up ( constant velocity ) only if sum of these two forces becomes equal to applied force

from the question,

weight of the carton,mg = 245 N

angle of incline,θ = 15°

coefficient of friction, μ = 0.340

∵ the applied force, F = mgsinθ + μmgcosθ

= mg ( sinθ + μcosθ)

= 245 ( sin 15° + 0.340 cos 15°)

= 245 ( 0.259 + 0. 328)

= 143.815 N