Answer:
If the volume of a cylinder is reduced from 8 L to 4 L the pressure of the gas in the cylinder will change from 70 kilopascals to 140 KPa.
Step-by-step explanation:
Given data:
Initial volume = 8 L
Final volume = 4 L
Initial pressure = 70 KPa
Final pressure = ?
Solution:
According to Boyles law:
P₁V₁ = P₂V₂
P₂ = P₁V₁ / V₂
P₂ = 70 KPa × 8 L/ 4 L
P₂ = 560 KPa. L/4 L
P₂ = 140 KPa
If the volume of a cylinder is reduced from 8 L to 4 L the pressure of the gas in the cylinder will change from 70 kilopascals to 140 KPa.