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2x+4y+2z= -8
5y-2z= 0
4z= -20

User StocksR
by
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1 Answer

4 votes

Answer:

The given solution for the system is x = 5, y = -2 and z = -5

Explanation:

Here, the given set of equations are:

2 x + 4 y +2 z = -8

5 y- 2 z = 0

4 z = -20

Now, simplifying each question one by one ,we get:

Simplifying third equation for the value of z:

4 z = -20 ⇒ z = -20 / 4 = - 5

or, z = -5

Simplifying second equation for the value of y:

Substitute the value of z = -5 in (2) , we get

5 y- 2 z = 0 ⇒ 5 y - 2(-5) = 0

or, 5 y + 10 = 0

or, 5 y = -10

or, y = -10/5 = -2

y = -2

Simplifying first equation for the value of x:

Substitute the value of z = -5 and y = -2 in (1) , we get

2 x + 4 y + 2 z = -8 ⇒ 2 x + 4 (-2) + 2 (-5) = -8

or, 2 x - 8 - 10 = -8

or, 2 x = 10

x = 10 / 2 = 5, or x = 5

Hence, the given solution for the system is x = 5, y = -2 and z = -5

User Jwayne
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