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The stopcock connecting a 2.25 L bulb containing oxygen gas at a pressure of 4.00 atm, and a 5.25 L bulb containing neon gas at a pressure of 8.00 atm, is opened and the gases are allowed to mix. Assuming that the temperature remains constant, what is the final pressure of the system in atm?

User A Cat
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1 Answer

6 votes

Answer:

The final pressure of the system is 6.8 atm

Step-by-step explanation:

Step 1: Data given

The oxygen bulb has a volume of 2.25L and pressure of4.00atm

The neon bulb has a volume of 5.25 L and a pressure if 8.00 atm

Step 2: Calculate the total volume

V1 + V2 = Vtotal

2.25 L + 5.25 L = 7.50 L

So the volume increases to 7.50 liters

Step 3: Calculate the partial pressure of oxygen

P1V1 = P'V'

P' = P1V1/V'

⇒with P1 = 4.00 atm

⇒ with V1 = 2.25 L

⇒ with P' = TO BE DETERMINED

⇒ with V' = 7.5 L

P' = (4*2.25) / 7.5

P' = 1.2 atm = partial pressure of oxygen

Step 4: Calculate partial pressure of neon

partial pressure of neon (8.00*5.25)/7.5 = 5.6 atm

Step 5: Calculate final pressure

The total pressure = 1.2atm + 5.6atm = 6.8 atm.

The final pressure of the system is 6.8 atm

User Fastec
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