Question

Here is a system of two linear equations. x + 3/4 y = 5 and x- 1/2 y = 0​

Answer 1

x = 2, y = 4

Explanation:

`\left\{\begin{array}{ccc}x+(3)/(4)y=5&\text{multiply both sides by 4}\\x-(1)/(2)y=0&\text{multiply both sides by 6}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}4x+3y=20\\6x-3y=0\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad10x=20\qquad\text{divide both sides by 10}\\.\qquad(10x)/(10)=(20)/(10)\\.\qquad\boxed{x=2}\\\\\\\text{Put it to the first equation:}\\\\4(2)+3y=20\\8+3y=20\qquad\text{subtract 8 from both sides}\\8-8+3y=20-8\\3y=12\qquad\text{divide both sides by 3}\\\boxed{y=4}`