Answer:
Scandium(III) fluoride, ScF3 , and Scandium(III) iodide, ScI3
Step-by-step explanation:
Although, Scandium is a soft metal with a silvery appearance, and develops a slightly yellowish when oxidized by air. It reacts with this elements all belonging to halogen family to form componds:
1. 2Sc(s) + 3F2(g) → 2ScF3(s)
Reacts with fluorine to form scandium(III) fluoride
2. 2Sc(s) + 3F2(g) → 2ScF3(s)
Reacts with iodine to form scandium(III) iodide
Compounds formed with Scandium are metallic as Scandium is found in a group in the periodic table known as the transition metals.