Question

Calculate the radius ratio for NaBr if the ionic radii of Na + and Br − are 102 pm and 196 pm , respectively. radius ratio: Based on the radius ratio, what is the expected coordination number of NaBr ? The range of radius ratios for each coordination number is given in parentheses.

Answer 1

Answer : The expected coordination number of NaBr is, 6.

Explanation :

Cation-anion radius ratio : It is defined as the ratio of the ionic radius of the cation to the ionic radius of the anion in a cation-anion compound.

This is represented by,

`(r_(cation))/(r_(anion))`

When the radius ratio is greater than 0.155, then the compound will be stable.

Now we have to determine the radius ration for NaBr.

Given:

Radius of cation,
`Na^+` = 102 pm

Radius of cation,
`Br^-` = 196 pm

`(r_(cation))/(r_(anion))=(102)/(196)=0.520`

As per question, the radius of cation-anion ratio is between 0.414-0.732. So, the coordination number of NaBr will be, 6.

The relation between radius ratio and coordination number are shown below.

Therefore, the expected coordination number of NaBr is, 6.