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Calculate the magnitude of q for a system that does 603000 kJ of work on its surroundings and for which the change in total internal energy is −1.80 × 104 kJ.

User Arty
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1 Answer

6 votes

Answer:

Q=585000 kJ

Step-by-step explanation:

Given Data

W (Work)=603000 kJ

ΔU (Change in total internal energy)=-1.80×10⁴ kJ

Q (Heat Supplied)=?

Solution

First Law of thermodynamic:

The first law of thermodynamics states that energy can neither be created nor destroyed, but only converted between various forms. For a closed system, we may write the change in internal energy as:

ΔU=Q-W

Q=ΔU+W

Q= -1.80×10⁴+603000

Q= 585000 kJ

User Nuno Linhares
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