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Find the midpoint of the line segment joining the points ​(10​,7​) and ​(negative 2​,negative 7​).

User Wootsbot
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1 Answer

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The midpoint of the line segment joining the points ​(10​,7​) and ​(negative 2​,negative 7​) is (4, 0)

Solution:

Given that line segment joining the points ​(10​,7​) and ​(negative 2​, negative 7​)

Thus the two points are ​(10​, 7​) and (-2, -7)

The midpoint of two points
(x_1, y_1) and
(x_2, y_2) is given as:


M(x, y)=\left((x_(1)+x_(2))/(2), (y_(1)+y_(2))/(2)\right)


\text {Here } x_(1)=10 \text { and } y_(1)=7 \text { and } x_(2)=-2 \text { and } y_(2)=-7

Substituting the values in formula, we get


\begin{array}{l}{M(x, y)=\left((10+(-2))/(2), (7+(-7))/(2)\right)} \\\\ {M(x, y)=\left((10-2)/(2), (7-7)/(2)\right)} \\\\ {M(x, y)=(4,0)}\end{array}

Thus the midpoint of line segment is (4, 0)

User SaeX
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