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F(x)=4x^2-x-3, find x when f(x)= -3

User Adrian May
by
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2 Answers

22 votes
22 votes

Answer:

x = 0 or x = 1/4

Explanation:

f(x) = 4x^2-x-3 = -3

4x^2 - x - 3 = -3

4x^2 - x = 0

x(4x - 1) = 0

x = 0 or 4x - 1 = 0

x = 0 or x = 1/4

User Dhinakar
by
2.4k points
28 votes
28 votes

Answer:

The values for x are x =0 x = 1/4

Explanation:

f(x)=4x^2-x-3

find f(x) = -3

Let f(x) = -3

Solve for x

-3 = 4x^2-x-3

Add 3 to each side

-3+3 = 4x^2-x-3+3

0 = 4x^2-x

Factor out an x

0 = x( 4x-1)

Using the zero product property

0 = x 4x-1 =0

0=x 4x=1

0=x x = 1/4

The values for x are x =0 x = 1/4

User Elmi Ahmadov
by
3.0k points