Question

In a perfectly elastic collision between billiard balls, croquet balls, or bocce balls, explain the relationship between the velocity of the moving ball before the collision and the formerly stationary ball after the c

Answer 1

u1 = \frac{(m1+m2)v}{m1}

Step-by-step explanation:

In a perfectly elastic collision,the bodies move together with a common velocity after collison.

let m1 represent the mass of body 1

m2 for mass of body 2

u1 is velocity of moving ball before collision

u2 is velocity of stationary ball before collision

v represents the common velocity of both bodies after collision.

u2=0, (body 2 is stationary)

we will substitute these variables into the formula

m1u1 + m2u2 =(m1+m2)v

m1u1 + m2 * 0 = (m1+m2)v

m1u1 = (m1+m2)v

u1 = \frac{(m1+m2)v}{m1}