Question

In humans , straight thumbs are dominant to hitchhiker's (bent) thumbs. What is the probability the offspring will have straight thumbs if you cross a homozygous dominant female with a heterozygous male?

A) 0%

B) 25%

C) 50%

D) 100%

Answer 1

50%

Step-by-step explanation:

I just did the punnett square here on paper I used the letter T for both parents. Tt is for the farther and tt is for the mother. Square 1 is Tt, Square 2 is tt, Square 3 is Tt, and Square 4 is tt. Proof it is 50% of the genes from both mother and father will go off into the offspring. If they have 2 offsprings 25% straight thumb 25% Hitchhiker thumb.

Answer 2

Option D

Step-by-step explanation:

Given

Straight thumbs are dominant to hitchhiker's (bent) thumbs.

Let straight thumbs be represented by "S" and bent thumbs be represented by "s"

Genotype of homozygous dominant female is SS

Genotype of heterozygous male is Ss

Cross between SS and Ss will produce following offspring

SS * Ss

SS, SS, Ss, Ss

All the off spring have straight thumb.

Thus, option D is correct