66.4k views
5 votes
Find the length of arc PQ. Round to the nearest tenth.

Find the length of arc PQ. Round to the nearest tenth.-example-1
User Harinath
by
8.4k points

2 Answers

3 votes

Answer : The length of arc PQ is, 8.1 in.

Step-by-step explanation :

First we have to calculate the ∠POQ.

As we know that a circle makes an angle of 360° at center.

That means,

∠POQ + ∠QOR + ∠ROS + ∠SOP = 360°

Given:

∠QOR = 65°

∠ROS = 150°

∠SOP = 73°

∠POQ + 65° + 150° + 73° = 360°

∠POQ + 288° = 360°

∠POQ = 360° - 288°

∠POQ = 72°

Now we have to calculate the length of arc PQ.

Formula used :

Length of arc PQ =
(\theta)/(360^o)* 2\pi r

where,


\theta=72^o

r = radius of circle = 6.48 in

Length of arc PQ =
(72^o)/(360^o)* 2* 3.14* 6.48in

Length of arc PQ = 8.1 in

Therefore, the length of arc PQ is, 8.1 in.

User Luming
by
8.1k points
3 votes

Answer:

The length of arc PQ to the nearest tenth is 8.1 inches.

Explanation:

Let the measure of arc PQ be 'x'.

Given:

The measure of arc SR = 150°

The measure of arc QR = 65°

The measure of arc PS = 73°

Radius of the circle is,
R=6.48\ in

Sum of the measures of all arcs in a circle is always 360°. Therefore,

Arc PQ + Arc QR + Arc SR + Arc PS = 360°


x+65+150+73=360\\x+288=360\\x=360-288=72\°

Now, the arc length is given as:


\textrm{Arc length}=R\theta\\Where\ \theta\rightarrow arc\ measure\ in\ radians

Now, measure of arc PQ,
\theta=72\°=72* (\pi)/(180)=0.4\pi

Therefore, arc length PQ =
6.48* 0.4\pi=2.592* 3.14=8.138\approx 8.1\ in

So, the length of arc PQ to the nearest tenth is 8.1 inches.

User Igrossiter
by
7.8k points

No related questions found