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A block with mass m = 4.3 kg is attached to two springs with spring constants kleft = 34 N/m and kright = 57 N/m. The b... ... The block is pulled a distance x = 0.22 m to the left of its equilibrium position and released from rest. 1). What is the magnitude of the net force on the block (the moment it is released)?

User Dorinda
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1 Answer

2 votes

Answer:

20.02 N

Step-by-step explanation:

The force the spring exerts is given by a law called Hooke's law


F=kx

where

k = Spring constant

x = Displacement


k_l = 34 N/m


k_r = 57 N/m

Here the block is pulled 0.22 to the left so it will also move 0.22 m to the right

So, the total force is given by


F=k_lx+k_rx\\\Rightarrow F=34* 0.22+57* 0.22\\\Rightarrow F=20.02\ N

The magnitude of the net force on the block is 20.02 N

User Blingers
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