Question

A 1.52-gram sample of iron (III) perchlorate was decomposed according to the reaction below, producing 575 mL of oxygen gas at 298K and 761 torr. Fe(ClO4)3 (s) -> FeCl3 (s) + 6 O2 (g) what volume of oxygen gas should be produced under conditions of STP from a 1.52-g sample of Fe(ClO4)3? Show all work

Answer 1

527.74 mL of oxygen gas should be produced under conditions of STP from a 1.52 grams sample of iron (III) perchlorate .

Step-by-step explanation:

Volume of the oxygen gas under given conditions
`V_1=575 mL`

Pressure of the oxygen gas ,
`P_1= 761 Torr =(761)/(760 )atm=1.0013 atm`

(1 atm = 760 Torr)

Temperature of the gas of the oxygen gas ,
`T_1=298 K`

At STP. the pressure of the gas =
`P_2=1 atm`

At STP, the temperature of the gas=
`T_2=273.15 K`

At STP. the volume of the oxygen gas =
`V_2`

Using combined gas law to find out the volume of oxygen gas at STP:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

`V_2=(P_1V_1* T_2)/(T_1* P_2)`

`V_2=(1.0013 atm* 575 mL* 273.15 K)/(298 K* 1 atm)`

`V_2=527.74 mL`

527.74 mL of oxygen gas should be produced under conditions of STP from a 1.52 grams sample of iron (III) perchlorate .