Question

A sample of an ideal gas has a volume of 3.55 L 3.55 L at 10.40 ∘ C 10.40 ∘C and 1.30 atm. 1.30 atm. What is the volume of the gas at 21.20 ∘ C 21.20 ∘C and 0.994 atm?

Answer 1

The volume of the gas at 21.2
`0^(2)`C and 0.994 atm is 4.8197

Step-by-step explanation:

he combined gas law makes use of the relationships shared by pressure, volume, and temperature: the variables found in other gas laws, such as Boyle's law, Charles' law and Gay-Lussac's law.

When we put Boyle's law, Charles' law, and Gay-Lussac's law together, we come up with the combined gas law, which shows that:

• Pressure is directly proportional to temperature, or higher temperature equals higher pressure.
• Volume is directly proportional to temperature, or higher temperature equals higher volume.
• Pressure is inversely proportional to volume, or higher volume equals lower pressure.

expressed mathematically as;

`(PV)/(T)   =   K`

The formula for the combined gas law can be adjusted to compare two sets of conditions in the same substance.

it is expressed as;

`(P_(1)V_(1)  )/(T_(1) ) = (P_(2)V_(2)  )/(T_(2) )`

`P_(1) = 1.30 atm        \\P_(2)  = 0.99  atm\\V_(1)  =  3.55L \\V_(2)  = ?\\T_(1) = 10.40^(o) C = 10.40^(o) C + 273^(o) C = 283.4 K\\T_(2) = 21.20^(o)C  + 273^(o)C  = 294.2 K`

`V_(2)  = (P_(1)V_(1)  T_(2)  )/(T_(1)P_(2)  )   =  (1.30 atm * 3.55 L * 294.2 K)/(283.4 K *0.99 atm)   = 4.8197 L`