149k views
3 votes
Write an inequality to represent the graph.

a solid line passing through points 0 comma 2 and 4 comma negative 1 with shading below the line

y is greater than or equal to negative four thirds times x plus 2
y is less than or equal to negative three fourths times x plus 2
y is greater than or equal to negative three fourths times x plus 2
y is less than or equal to negative four thirds times x plus 2

User Karan Garg
by
8.4k points

1 Answer

6 votes

Answer:


y \leq -(3)/(4)x+2

y is less than or equal to negative three fourths times x plus 2

Explanation:

step 1

Find the slope of the solid line

we have the ordered pairs

(0,2) and (4,-1)

Find the slope m


m=(-1-2)/(4-0)


m=-(3)/(4)

step 2

Find the linear equation of the solid line in slope intercept form


y=mx+b

we have


m=-(3)/(4)


b=2 ---> the y-intercept is given

substitute


y=-(3)/(4)x+2

step 3

Find the inequality

Remember that the solution is the shaded area below the solid line

therefore

The inequality is


y \leq -(3)/(4)x+2

y is less than or equal to negative three fourths times x plus 2

User Alex Nichol
by
8.2k points