Answer:
Step-by-step explanation:
The equation for this chemical reaction is:
2Ca + O2 -> 2CaO
So 2 moles of Ca react with 1 mole of O2 to form 2 moles of CaO.
Given 3.9 moles of Ca and 2.35 moles of O2,
Ca is the greater reactant as it will be used up.
O2 is the reactant in excess and there will be 2.35 - 3.9/2 = 0.4 moles left.
As mass of 1 mole of O2 is 32g, 0.4 moles of O2 = 0.4 * 32 = 12.8g
Moles of CaO formed = moles of Ca = 3.9
As mass of 1 mole of O2 is 56g, 3.9 moles of CaO = 3.9 * 56 = 218.4g of CaO