Question

Given the following data, determine the order of reaction with respect to H2.

H2(g)+ 2ICI → I2(g)+ 2HCL(g)

Experiment [H2](torr) ICI[torr] Rate(M/s)
1 250 325 1.34
2 250 81 0.331
3 50 325 0.266

Answer 1

First-order with respect to hydrogen.

Step-by-step explanation:

Hello!

In this case, considering that the rate law of this reaction can be expressed via:

`r=k*p_(H_2)^m*p_(ICl)^n`

If we want to know m, the order of reaction with respect to hydrogen, we need to relate the experiments 1 and 3 in order to get rid of the pressure of ICl:

`(r_1)/(r_3) =(k*p_(H_2,1)^m*p_(ICl,1)^n)/(k*p_(H_2,3)^m*p_(ICl,3)^n)`

Thus, we plug in the given rates, and pressures to get:

`(1.34)/(0.266) =(k*250^m*325^n)/(k*50^m*325^n)`

So we can cancel wout k and 325^n:

`(1.34)/(0.266) =(250^m)/(50^m)`

Next we solve for m, the order of reaction with respect to hydrogen:

`5.04 =5^m\\\\log(5.04)=m*log(5)\\\\m=(log(5.04))/(log(5)) \\\\m=1.0`

It means it is first-order with respect to hydrogen.

Regards!