Question

How many moles of CO2 are produced when 0.400 moles of C6H12O6 react and are decomposed ​

Answer 1

0.800 moles of
`CO_2` will be produced when 0.400 moles of
`C_6H_1_2O_6` react and are decomposed

Step-by-step explanation:

The decomposition of
`C_6H_1_2O_6[/te can be written as </p><p>[tex]C_6H_1_2O_6` (aq) ------> 2C2H5OH (aq) + 2CO2

¬moles of
`C_6H_1_2O_6` = 0.400 moles

Moles of
`CO_2` produced will be calculated by the formula,

Moles of CO2 = 0.400 moles of
`C_6H_1_2O_6`
`\left(\frac{2 \text { moles of } \mathrm{CO}_(2)}{1 \text { mole of } C_(6) \mathrm{H}_(12) \mathrm{O}_(6)}\right)`

Substituting the values,

Moles of
`CO_2` =
`(0.400 * 2)/(1)` = 0.400*2 = 0.800 moles

Therefore, 0.800 moles of
`CO_2` will be produced when 0.400 moles of
`C_6H_1_2O_6` react and are decomposed