Question

The partition coefficient for caffeine between dichloromethane and water is 4.6. Assume that your 100 mL tea solution (in water) contained 0.10 g of caffeine. What is your theoretical yield of caffeine if: You extract with only one 15 mL portion of CH2Cl2?

Answer 1

Theoretical yield is 0,041g of caffeine

Step-by-step explanation:

The partition coefficient formula is:

`k = (CaffeineDichloromethane)/(CaffeineWater)`

Where k is partition coefficient (4,6)

The Caffeine in water at equilibrium will have a concentration of:

(0,10g-x) / 100mL

And Caffeine in dichloromethane will be:

xg / 15mL -Where x grams are the theoretical yield of caffeine-

Replacing:

`4,6 = (X/15)/((0,10g-X)/100)`

`4,6 = (100X)/(15(0,10g-X))`

`4,6 = (100X)/(1,5-15X)`

6,9 - 69X = 100X

6,9 = 169X

0,041 g = X

I hope it helps!