Question

A rectangle has a length six inches less than twice its width. If the perimeter of the rectangle is 54 inches, find the dimensions.​

Answer 1

let the width of the rectangle be x inches

then the length would be 2x-6

as perimeter =2(l+b)

putting values in formula

perimeter = 2(2x-6+x)

p= 6x-12 but as perimeter p=54inches so

54=6x-12

54+12=6x

66=6x

x=66/6

x=11 inches

width is 11inches and length is 2x-6= 2(11)-6=22-6=16 inches

Explanation: