Question

Thanks for all the help!

Answer 1

12.
`\displaystyle NO\:SOLUTION`

11.
`\displaystyle 0, 7 = x\:[where\:0\:is\:the\:extraneous\:solution]`

10.
`\displaystyle -3 = x`

9.
`\displaystyle [x - 5]^(-1)`

Step-by-step explanation:

All work is shown above.

*
`\displaystyle (1)/(x - 5) = [x - 5]^(-1)`

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