Question

Hello....I need help with this question.

If the velocity of a moving car increases from 9.0 m/s to 25.0 m/s in the span of 5 seconds, what is the average acceleration during this time period, in m/s2

Answer 1

These are the steps to solving your question

Answer 2

3.2 m/s²

Step-by-step explanation:

Acceleration can be calculated as:

v = u + at (where v is final velocity, u is initial velocity, a is acceleration and t is time)

25 m/s = 9 m/s + a(5 s) (a is unknown)

16 m/s = a(5 s)

a = 3.2 m/s²

We assume that this is a uniform acceleration (meaning that the velocity increases at an equal rate for those 5 seconds).