Question

When ethane C2H6) burns, it produces carbon dioxide and water:

2C3H5(0) +702(g) → 4CO2(g) + 6H2011)
How many liters of carbon dioxide will be produced when 269 L of ethane are
burned? (One mole of any gas occupies 22.4 L under certain conditions of
temperature and pressure. Assume those conditions for this question.)

Answer 1

538L of carbon dioxide will be produced

Step-by-step explanation:

This is a classic example of combustion of an alkane.

If balanced equation is not given; this format can come in handy.

For any alkane of the type : CₙH₂ₙ₊₂ , it's combustion reaction will follow:

2CₙH₂ₙ₊₂ + (3n+1) O₂ → (2n)CO₂ + 2(n+1) H₂O

For ethane:

2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(l)

Here, 2 mole of ethane gives 4 moles of CO₂.

or,
`2 * 22.4L` of ethane gives
`4 * 22.4L` of CO₂.

Then, 269L of ethane will give:

=
`(269 * 4 * 22.4)/(2 * 22.4)`

=
`269 * 2` L

= 538 L

Therefore, 538L of carbon dioxide will be produced