Question

Consider the balanced chemical reaction below and determine the percent yield for iron if 11.2 moles of Iron(III) oxide yielded 17.4 moles of iron

Fe2O3+3CO>2Fe+3CO2

Answer 1

Answer: 77.68

Step-by-step explanation:

Answer 2

The yield percent is 77.68%

Step-by-step explanation:

`Fe_(2)O_(3)+3CO\longrightarrow2Fe+3CO_(2)`

1 mole of
`Fe_(2)O_(3)` yields 2 moles of Fe.

So, 11.2 moles of Iron(III) oxide must yield 22.4 moles of Fe theoretically. This is according to the balanced equation.

Theoretical Yield = 22.4 moles of Fe

Experimental Yield = 17.4 moles of Fe

`Yield\:Percentage=(Experimental\:Yield)/(Theoretical\:Yield)*100\\\\Yield\:Percentage=(17.4)/(22.4)*100=77.68\%`

Therefore, the yield percent is 77.68%