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20 votes
20 votes
Solve the system of equations.
2x+ 27 + 32 = 5
6x + 3y + 62 = 6
3x + 41 + 42 = 9

Solve the system of equations. 2x+ 27 + 32 = 5 6x + 3y + 62 = 6 3x + 41 + 42 = 9-example-1
User Agyemang
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1 Answer

27 votes
27 votes

Answer:

x=-1

y=2

z=1

Explanation:

After substitution we add common terms and make y and z the subject

y= 3-z

z= - 3+ 2y

We substitue the y

z = - 3+2(3-z)

z= 1

and now we subtitute the z to find y

y= 3-z

3-1 = 2

y=2

Now we substitue y and z to find x

x= - 2 - 3/2 + 5/2

x= - 1

Solve the system of equations. 2x+ 27 + 32 = 5 6x + 3y + 62 = 6 3x + 41 + 42 = 9-example-1
User Andymurd
by
2.6k points