Answer:
H_0: p = 19%\\H_a: p>19%
Explanation:
Given that more than 19% of workers indicate that they are mildly satisfied with their job.
To test whether this proportion given is actually right, we can draw random samples of large size and do hypothesis test.
For that we have to create hypotheses with null always = some value while alternate may be either not equal to or greater than or less than
Since here claim is that more than 19% of workers indicate that they are mildly satisfied with their job we can test the claim whether p >19%
So hypotheses would be
![H_0: p = 19%\\H_a: p>19%\\](https://img.qammunity.org/2020/formulas/mathematics/college/68dxb2yphb9x8o01pio8hynw75u21ge9am.png)
This is right tailed test for testing of a single proportion.