Question

Nov 13, 11:33:36 AM

Jeremiah is blocking off several rooms in a hotel for guests coming to his wedding.

The hotel can reserve small rooms that can hold 3 people, and large rooms that can

hold 4 people. Jeremiah reserved twice as many small rooms as large rooms, which

altogether can accommodate 50 guests. Determine the number of small rooms

reserved and the number of large rooms reserved.

There were

small rooms reserved and

large rooms reserved.

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Answer 1

10 small rooms

5 large rooms

Explanation:

Let the number of small rooms reserved be s and the number of large rooms reserved be l.

Now what do we know. We know quite well that the small rooms can accommodate 3 guests while the large rooms can accommodate 4 guests. This means the following in equation form:

3s + 4l = 50 ......(I)

Also we know that she reserved twice as many small rooms as large rooms.

s= 2l........(II)

Substitute 2 into 1

3(2l) + 4l = 50

10l = 50

l = 5

Since, s = 2l , this implies s = 2 * 5 = 10